C++ Program To Find Whether The Number is Even or Odd

Even Numbers : Any digit or number which can be divided by 2 or groups of 2 are called as even numbers. 

Numbers like 0 , 2 , 4 , 6 , 8 , 10 , 12 , 16 ...

Odd Numbers   : Numbers other than even numbers are called as odd numbers.

Numbers like 1 , 3 , 5 , 7 , 9 , 11 , 13 , 15 ...

Algorithm:

Need to check which numbers are divided by 2.

Program code:

#include<iostream>

#include<conio.h>

using namespace std;

int main()

{

  int number;

  char redo;

  

  cout<<"*************************************"<<endl;

  cout<<"           Even or Odd               "<<endl;

  cout<<"*************************************"<<endl<<endl;

 do

 {

    cout<<"Enter any Number  =  ";

    cin>>number;

    cout<<endl<<endl;

    

  

    if(number%2==0)

    cout<<number <<"  =  Even Number "<<endl<<endl;

  

    else

    cout<<number<< "  =  Odd  Number "<<endl<<endl;

    

    cout<<"*************************************"<<endl<<endl;

    

    cout<<"Enter y or Y for next number  =  ";

    cin>>redo;

    cout<<endl<<endl;

  }while(redo == 'y' || redo == 'Y' );

   getch();

}

Output: After compile and run ,, the output will be like this

Click on pic to enlarge it.

Hope that you will find this helpful.